1.+Mult+&+Div+by+powers+of+10

=Multiplication and Division by powers of 10=

There are two type of numbers that are powers of 10
> > == ==
 * ==multiplication - numbers greater than one==
 * examples are 10, 100, 1000, 10000, and so on...
 * count the number of zeros and move the decimal to the **right**
 * add extra zeros if necessary
 * problem #1: **12.34 x 100**
 * 100 has two zeros, so shift the decimal __twice__ to the right
 * the answer is 1234
 * problem #2: **1.7 x 1000**
 * 1000 has three zeros, so shift the decimal __three__ times to the right
 * I added __two__ new zeros
 * the answer is 1700
 * ==multiplication - numbers less than one==
 * examples are 0.1, 0.01, 0.001, 0.001, and so on...
 * count the number of decimal places you would need to shift the decimal to get it to the right of the 1
 * shift the decimal to the **left** the number of decimal places from above
 * add leading zeros if necessary
 * problem #1: **1.23 x 0.01**
 * you would move the decimal __two__ places to get it on the right side of the number one
 * I added __one__ extra (leading) zero
 * the answer is 0.0123
 * problem #2: **1.7 x 0.001**
 * you would move the decimal __three__ places to get it on the right side of the number one
 * I added __two__ extra (leading) zeros
 * the answer is 0.0017
 * ==Division - numbers less than one==
 * examples are 0.1, 0.01, 0.001, 0.001, and so on...
 * count the number of decimal places you would need to shift the decimal to get it to the right of the 1
 * shift the decimal to the **right** the number of decimal places from above
 * add leading zeros if necessary
 * problem #1: **1.23 / 0.01**
 * you would move the decimal __two__ places to get it on the right side of the number one
 * the answer is 123
 * it may seem weird that dividing makes the result bigger, but think about cookies.
 * If you divide 4 cookies by 0.5 (same as breaking them in half, then you have 8 portions!
 * problem #2: **1.7 x 0.001**
 * you would move the decimal __three__ places to get it on the right side of the number one
 * I added __two__ extra (leading) zeros
 * the answer is 0.0017
 * ==Division - numbers more than one==
 * ** examples are 10, 100, 1000, 10000, and so on...
 * count the number of zeros and move the decimal to the **left**
 * add extra zeros if necessary
 * problem #1: **12.34 / 100**
 * 100 has two zeros, so shift the decimal __twice__ to the left
 * the answer is 0.1234
 * problem #2: **1.7 / 1000**
 * 1000 has three zeros, so shift the decimal __three__ times to the left
 * I added __two__ new (leading) zeros
 * the answer is 0.0017